# Identify the vertex and the axis of symmetry of the graph of the function y = 2(x+2)^{2} - 4

**Solution:**

It is given that,

y = 2(x + 2)^{2} - 4

We know that the equation of a vertical parabola into vertex form is equal to,

y = a(x - h)^{2} + k

where, (h, k) is the vertex of the parabola,

So, the axis of symmetry of a vertical parabola is equal to

x = h … [the x coordinate of the vertex]

Then,

y = 2(x + 2)^{2} - 4

The vertex point (-2, -4)

Hence the axis of symmetry is equal to the coordinate of the vertex,

x = -2

Therefore, the vertex and the axis of symmetry of the graph of the function y = 2(x+2)^{2} - 4 are (-2, -4) and x= -2 respectively.

## Identify the vertex and the axis of symmetry of the graph of the function y = 2(x+2)^{2} - 4

**Summary:**

The vertex and the axis of symmetry of the graph of the function y = 2(x+2)^{2} - 4 are (-2, -4) and x= -2 respectively.

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