If h(x) = x² + 1, k(x) = x - 2, (h + k)(2) = ?

Solution:

A function is a process or a relation that associates each element 'a' of a non-empty set A , at least to a single element 'b' of another non-empty set B.

A relation f from a set A (the domain of the function) to another set B (the co-domain of the function) is called a function in math.

Given, functions are h(x) = x² + 1

k(x) = x - 2

We have to find (h + k)(2)

(h + k)(x) = h(x) + k(x)

= (x² + 1) + (x - 2)

= x² + 1 + x - 2

= x² + x - 1

Put x = 2 in the above expression,

(h + k)(2) = (2)² + 2 - 1

= 4 + 2 - 1

= 6 - 1

= 5

Therefore, (h + k)(2) is 5.

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If h(x) = x² + 1, k(x) = x - 2, (h + k)(2) = ?

Summary:

If h(x) = x² + 1, k(x) = x - 2, (h + k)(2) = 5. A relation f from a set A (the domain of the function) to another set B (the co-domain of the function) is called a function in math.