If x > 2, then x2 - x - 6/x2 - 4 =
Solution:
It is given that equation is
(x2 - x - 6)/(x2 - 4)
By splitting the middle term we get
= (x2 - 3x + 2x - 6)/ (x2 - 4)
Using the algebraic identity
a2 - b2 = (a + b) (a - b)
= (x2 - 3x + 2x - 6)/ (x + 2) (x - 2)
Taking out the common terms
= [x(x - 3) + 2(x - 3)]/ (x + 2)(x - 2)
= (x + 2)(x - 3)/ (x + 2)(x - 2)
So we get
= (x - 3)/ (x - 2)
Therefore, x2 - x - 6/x2 - 4 = (x - 3)/ (x - 2).
If x > 2, then x2 - x - 6/x2 - 4 =
Summary:
If x > 2, then x2 - x - 6/x2 - 4 = (x - 3)/ (x - 2).
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