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# Solve for x, 2x^{2} = 128

**Solution:**

Given: Equation is 2x^{2} = 128.

Let us use the algebraic identity to solve the equation.

2x² = 128 can be expressed as 2x^{2} - 128 = 0.

**By taking out the common terms, we get**

2 (x^{2} - 64) = 0

x^{2} - 64 = 0 [By using the zero product rule]

**By using algebraic identity,**

a^{2} - b^{2 }= (a - b) (a + b)

(x)^{2} - (8)^{2} = (x - 8) (x + 8) = 0

**Considering the two factors equal to zero, we get**

x - 8 = 0 and x + 8 = 0

x = 8 and x = - 8.

Hence, the solution of the equation 2x^{2} = 128 is x = 8 and -8.

## Solve for x, 2x^{2} = 128

**Summary:**

The equation 2x² = 128 has two solutions x = 8, and - 8.

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