Solve x² + 2x + 1 = 17 for x.

Solution:

Given x² + 2x + 1 = 17

This is a polynomial of degree 2

Quadratic equations are second-degree algebraic expressions and are of the form ax² + bx + c = 0.

x² + 2x + 1 -17=0

x² + 2x -16 = 0

Here we use quadratic formula for finding roots of the equation

x = {-b ± √b² - 4ac}/2a

Here a = 1; b = 2; c = -16

x = {-2 ± √2² - 4(-16)} /2(1)

x = {-2 ± √4 + 64} /2

x = {-2 ± √68 } /2

x = {-2 ± 8.24} /2

x = -5.12, 3.12

The roots are -5.12, 3.12

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Solve x² + 2x + 1 = 17 for x.

Summary:

By solving x² + 2x + 1 = 17, we get x values as -5.12, 3.12