The sum of three consecutive even integers is 108. What is the largest number?

Solution:

Given,

The sum of three consecutive even integers is 108.

Let the three consecutive even numbers be 2x, 2x + 2,and 2x + 4

Adding we get,

2x + 2x + 2 + 2x + 4 = 108

2x + 2x + 2x + 2 + 4 = 108

6x + 6 = 108

6(x + 1) = 108

x + 1 = 18

x = 17.

Substituting x we get,

2x = 2(17) = 34

2x + 2 = 34 + 2 = 36

2x + 4 = 34 + 4 = 38.

Therefore, the largest number is 38.

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The sum of three consecutive even integers is 108. What is the largest number?

Summary:

The sum of three consecutive even integers is 108. The largest number is 38.