What is the equation in point-slope form of the line passing through (-2, 1) and (4, 13)?
y - 1 = -2(x - 4)
y - 1 = 2(x + 2)
y - 13 = -2(x + 2)
y - 13 = 2(x + 4)

Solution:

Given points are (x₁, y₁) = (-2, 1)

(x₂, y₂) = (4, 13)

Slope,

m = (y₂ - y₁)/(x₂ - x₁)

= (13 - 1)/(4 - (-2))

= 12/6

= 2

Equation of line in point-slope form is (y - y₁) = m (x - x₁) .

If (x₁, y₁) = (-2, 1) ⇒ equation is (y - 1) = 2(x + 2).

Therefore, equation in point-slope form is (y - 1) = 2(x + 2).

What is the equation in point-slope form of the line passing through (-2, 1) and (4, 13)?

Summary:

The equation in point-slope form of the line passing through (-2, 1) and (4, 13) is (y - 1) = 2(x + 2).