What is the equation in point-slope form of the line passing through (3, 6) and (-2, 1)?
y + 6 = 1(x + 3)
y + 1 = -1(x + 2)
y - 6 = -1(x + 3)
y - 6 = 1(x - 3)

Solution:

Given points are (x₁, y₁) = (3, 6)

(x₂, y₂) = (-2, 1)

Slope, m = (y₂ - y₁)/(x₂ - x₁)

= (1 - 6)/(-2 - 3)

= (-5)/(-5)

m = 1

Equation of line in slope point form is (y - y₁) = m (x - x₁) .

If (x₁, y₁) = (3, 6),

Equation is (y - 6) = 1(x - 3).

Therefore, the equation in point-slope form is (y - 6) = 1(x - 3).

What is the equation in point-slope form of the line passing through (3, 6) and (-2, 1)?

Summary:

The equation in point-slope form of the line passing through (3, 6) and (-2, 1) is (y - 6) = 1(x - 3).