What is the f of x over the g of x when f(x) = -2x3 + x2 + 16x - 15 and g(x) = x + 3?
Solution:
It is given that,
f(x) = -2x3 + x2 + 16x - 15 and g(x) = x + 3
Now we have to find f of x over the g of x.
By using long division method,
Therefore, the f of x over the g of x is -2x2 + 7x - 5.
What is the f of x over the g of x when f(x) = -2x3 + x2 + 16x - 15 and g(x) = x + 3?
Summary:
The f of x over the g of x when f(x) = -2x3 + x2 + 16x - 15 and g(x) = x + 3 is -2x2 + 7x - 5.