What is the f of x over the g of x when f(x) = -2x³ + x² + 16x - 15 and g(x) = x + 3?

Solution:

It is given that,

f(x) = -2x³ + x² + 16x - 15 and g(x) = x + 3

Now we have to find f of x over the g of x.

By using long division method,

Therefore, the f of x over the g of x is -2x² + 7x - 5.

What is the f of x over the g of x when f(x) = -2x³ + x² + 16x - 15 and g(x) = x + 3?

Summary:

The f of x over the g of x when f(x) = -2x³ + x² + 16x - 15 and g(x) = x + 3 is -2x² + 7x - 5.