What is the logarithmic form of the equation e2x ≈ 1732?
Solution:
Given the equation e2x ≈ 1732
This is in exponential form.
To convert this to the logarithmic form, use this formula:
If ab = x then logax = b
The logarithm base (e) 1732 = 2x
⇒Loge1732 = 2x
What is the logarithmic form of the equation e2x ≈ 1732?
Summary:
The logarithmic form of the equation e2x ≈ 1732 is loge1732 = 2x.
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