What is the remainder when (3x⁴ + 2x³ - x² + 2x - 9) ÷ (x + 2)?

Solution:

We have to find the remainder when (3x⁴ + 2x³ - x² + 2x - 9) ÷ (x + 2)

Here the dividend is 3x⁴ + 2x³ - x² + 2x - 9 and the divisor is x + 2.

By long division method

Therefore, the remainder is 15.

What is the remainder when (3x⁴ + 2x³ - x² + 2x - 9) ÷ (x + 2)?

Summary:

The remainder when (3x⁴ + 2x³ - x² + 2x - 9) ÷ (x + 2) is 15.