What is the slope of a line that is perpendicular to a line whose equation is 3y = -4x + 2?

Solution:

Given, the equation of the line is 3y = -4x + 2

The equation can be rewritten as y = -4x/3 + 2/3 --- (1)

The equation of the line in slope-intercept form is given by

y = mx+c --- (2)

Where, m = slope

y indicates how far up or down is the line

x indicates how far along is the line

c indicates the value of y when x = 0

Comparing (1) and (2)

m = -4/3

Slope of the line is -4/3.

Slope of the perpendicular line = -1/m

= -(-3/4)

= 3/4

Therefore, the slope of the perpendicular line is 3/4.

What is the slope of a line that is perpendicular to a line whose equation is 3y = -4x + 2?

Summary:

The slope of a line that is perpendicular to a line whose equation is 3y = -4x + 2 is 3/4.