What is the slope of a line that is perpendicular to the line whose equation is 2y = 3x - 1?

Solution:

We know that the equation of the line in its slope-intercept form is y = mx+b, 

A line that is perpendicular to it is y = -1/m x + b

The slope of the perpendicular line is -1/m

Rewriting the given equation, we get y = 3/2 x - 1/2

So the slope of the perpendicular line is the reciprocal of 3/2 which is multiplied by -1. 

The slope of the line = -2/3

Therefore, the slope of a line that is perpendicular to the line whose equation is 2y = 3x - 1 is -2/3.

What is the slope of a line that is perpendicular to the line whose equation is 2y = 3x - 1?

Summary:

The slope of a line that is perpendicular to the line whose equation is 2y = 3x - 1 is -2/3.