# What is the value of b^{2} - 4 ac for the following equation x^{2} + 5 x + 4 = 0?

A quadratic equation is represented as ax^{2} + bx + c = 0 where a ≠ 0. The degree of a quadratic equation is equal to 2.

## Answer: The value of b^{2} - 4ac that satisfies the equation x^{2} + 5 x + 4 = 0 is 9.

Let's find the value of b^{2} - 4ac.

**Explanation:**

A discriminant of a quadratic equation is a function of the coefficients of the polynomials.

The discriminant is denoted as 'D' and is given as,

D = b^{2} - 4ac

Given equation is x^{2} + 5 x + 4 = 0.

Where,

a = coefficient of x^{2}, b = coefficient of x and c = constant term.

Thus, a = 1, b = 5, c = 4

D = ( 5 )^{2} - [4 × 1 × ( 4 )]

= 25 - 4 × ( 4)

= 25 - 16

= 9

We can also use the online discriminant calculator to calculate the discriminant.