What values of b satisfy 4(3b + 2)² = 64?

An equation is a mathematical statement with an 'equal to' symbol between two algebraic expressions that have equal values.

Answer: The values of b satisfying  4(3b + 2)² = 64 are b = 2 ,b = -6

An equation is like a weighing balance with equal weights on both sides. If we add or subtract the same number from both sides of an equation, it still holds.

Explanation:

4 (3b + 2)² = 64

dividing by 4 on  both sides, we have

(3b + 2)² = 16

taking square root on both sides

3b + 2 = ± 4

3b = ± 4 - 2

b = 2 , -6

So, the required values of b are 2 , -6