What values of b satisfy 4(3b + 2)² = 64?

Solution:

An equation is a mathematical statement with an 'equal to' symbol between two algebraic expressions that have equal values.

Given 4 (3b + 2)² = 64

Dividing by 4 on  both sides, we have

(3b + 2)² = 16

Taking square root on both sides

3b + 2 = ± 4

3b = ± 4 - 2

b = 2 , -6

So, the required values of b are 2 , -6

What values of b satisfy 4(3b + 2)² = 64?

Summary:

The values of b satisfying  4(3b + 2)² = 64 are b = 2 ,b = -6