What values of b satisfy 4(3b + 2)2 = 64?
Solution:
An equation is a mathematical statement with an 'equal to' symbol between two algebraic expressions that have equal values.
Given 4 (3b + 2)2 = 64
Dividing by 4 on both sides, we have
(3b + 2)2 = 16
Taking square root on both sides
3b + 2 = ± 4
3b = ± 4 - 2
b = 2 , -6
So, the required values of b are 2 , -6
What values of b satisfy 4(3b + 2)2 = 64?
Summary:
The values of b satisfying 4(3b + 2)2 = 64 are b = 2 ,b = -6
Math worksheets and
visual curriculum
visual curriculum