# Write an equation of the line that passes through the points (0, 1) and (-2, -5).

**Solution:**

The general equation of a straight line can be written as y = mx + c where m is the slope and c is the y-intercept.

Let us consider the given points (0, 1) and (-2, -5).

As we know that the equation of a line passing through the points (x_{1},_{ }y_{1}) and (x_{2}, y_{2}) is given by y - y_{1} = m (x - x_{1}).

Here, m is the slope given by the formula m = (y_{2} - y_{1}) / (x_{2} - x_{1}). Check out Cuemath's Slope Calculator that helps you to calculate the slope.

Hence, on substituting the given points in the equation of a line, we get

y - 1 = m (x - 0)

m = (y_{2} - y_{1}) / (x_{2} - x_{1})

m = (-5 - 1) / (-2 - 0)

m = -6 / -2 = 3

Substituting the value of m in y - 1 = m (x - 0), we get

y - 1 = 3 (x - 0)

y - 1 = 3x

y = 3x + 1

y - 3x -1 = 0

You can use Cuemath's online Equation of Line calculator to find the equation of a line.

Therefore, the equation of a line passing through the points (0, 1) and (-2, -5) is y - 3x -1 = 0

## Write an equation of the line that passes through the points (0, 1) and (-2, -5).

**Summary:**

The equation of a line through the points (0, 1) and (-2, -5) is y - 3x - 1 = 0

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