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# Write the equation in standard form. Then factor the left side of the equation. 3x^{2} + 19x = 14

**Solution:**

Given: Equation is 3x^{2 }+ 19x = 14

This quadratic equation can be written in standard form as

3x^{2} + 19x - 14 = 0

Let us factorize it by splitting the middle term

3x^{2} - 2x + 21x - 14 = 0

Take out the common factors

x(3x - 2) + 7(3x - 2) = 0

(3x - 2)(x + 7) = 0

Therefore, the equation in standard form is 3x^{2} + 19x - 14 = 0 and by factorization we get (3x - 2) (x + 7) = 0.

## Write the equation in standard form. Then factor the left side of the equation. 3x^{2} + 19x = 14

**Summary:**

The equation in standard form is 3x^{2} + 19x - 14 = 0 then by factoring the left side of the equation, we get (3x - 2)(x + 7) = 0.

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