# (a) Construct 3 equations starting with x = 2

(b) Construct 3 equations starting with x = −2

**Solution:**

We use the basic concepts of simple linear equations to solve the problem.

We can get the equation by adding, multiplying or subtracting the same value on both sides of the equation.

(a) 3 equations starting with x = 2

(i) x = 2

Multiplying both sides by 10,

10x = 20

Adding 2 to both sides ,

10x + 2 = 20 + 2

10x + 2 = 22

(ii) x = 2

Multiplying both sides by 5,

5x = 10

Subtracting 3 from both sides,

5x − 3 = 10 − 3

5x − 3 = 7

(iii) x = 2

Multiplying both sides by 2,

2x = 4

Subtracting 3 from both sides,

2x − 3 = 4 − 3

2x − 3 = 1

(b) 3 equations starting with x = −2

(i) x = −2

Multiplying both sides by 3,

3x = −6

Adding 1 to both the sides,

3x + 1 = - 6 + 1

3x + 1 = - 5

(ii) x = −2

Multiplying both sides by 3,

3x = − 6

Adding 7 to both sides we get.

3x + 7 = −6 + 7

3x + 7 = 1

(iii) x = −2

Multiplying both sides by 3,

3x = −6

Adding 10 to both sides, we get

3x + 10 = −6 +10

3x + 10 = 4

**☛ Check: **NCERT Solutions Class 7 Maths Chapter 4

**Video Solution:**

## (a) Construct 3 equations starting with x = 2 (b) Construct 3 equations starting with x = −2

NCERT Solutions for Class 7 Maths Chapter 4 Exercise 4.3 Question 4

**Summary:**

(a) 3 equations starting with x = 2 are i) 10x + 2 = 22 , ii) 5x − 3 = 7 , iii) 2x − 3 = 1 and (b) 3 equations starting with x = −2 are i) 3x + 1 = − 5 , ii) 3x + 7 = 1 , iii) 3x + 10 = 4

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