# (a) Construct 3 equations starting with x = 2

(b) Construct 3 equations starting with x = −2

**Solution:**

We use the basic concepts of simple linear equations to solve the problem.

You can get the equation by adding, multiplying or subtracting the same value on both sides of the equation.

(a) 3 equations starting with x = 2

(i) x = 2

Multiplying both sides by 10,

10 x = 20

Adding 2 to both sides ,

10 x + 2 = 20 + 2

10 x + 2 = 22

(ii) x = 2

multiplying both sides by 5,

5 x = 10

subtracting 3 to both sides,

5 x − 3 = 10 − 3

5 x − 3 = 7

(iii) x = 2

multiplying both sides by 2,

2 x = 4

subtracting 3 to both sides,

2 x − 3 = 4 −3

2 x − 3 = 1

(b) 3 equations starting with x = −2

(i) x = −2

Multiplying both sides by 3,

3 x = −6

(ii)x = −2

Multiplying both sides by 3,

3 x = −6

Adding 7 to both sides we get.

3 x + 7 = −6 + 7

3 x + 7 = 1

(iii) x = −2

Multiplying both sides by 3,

3 x = −6

Adding 10 to both sides, we get

3 x + 10 = −6 +10

3 x + 10 = 4

**Video Solution:**

## (a) Construct 3 equations starting with x = 2 (b) Construct 3 equations starting with x = −2

### NCERT Solutions for Class 7 Maths - Chapter 4 Exercise 4.3 Question 4

(a) Construct 3 equations starting with x = 2 (b) Construct 3 equations starting with x = −2

(a) i) 10 x + 2 = 22 , ii) 5 x − 3 = 7 , iii) 2 x − 3 = 1 , (b) i) 3 x = −6 , ii) 3 x + 7 = 1 , iii) 3 x = −6