# Solve the following equations.

(a) 4 = 5(p – 2) (b) –4 = 5(p – 2)

(c) 16 = 4 + 3(t + 2) (d) 4 + 5(p – 1) = 34

(e) 0 = 16 + 4(m – 6)

**Solution:**

We use the concepts of simple linear equations and fundamental operations like addition, subtraction, multiplication and division to solve the problem.

First, we formulate the word problems in terms of linear equations in one variable.

Transpose the variables on the one side and constants on the other side, then simplify them and get the value of a variable.

(a) 4 = 5(p - 2)

4 = 5p - 10

5p = 4 + 10

Therefore, p = 14/5

(b) -4 = 5(p - 2)

-4 = 5p- 10

-4 + 10 = 5p

6 = 5p

Therefore, p = 6/5

(c) 16 = 4 + 3(t + 2)

16 = 4 + 3t + 6

16 - 10 = 3t

6 = 3t

t = 6/3 = 2

d) 4 + 5(p - 1) = 34

4 + 5p - 5 = 34

5p - 1 = 34

5p = 35

p = 35/5

p = 7

(e) 0 = 16 + 4(m - 6)

0 = 16 + 4m - 24

8 = 4m

m = 8/4

m = 2

**Video Solution:**

## Solve the following equations. (a) 4 = 5(p – 2) (b) – 4 = 5(p – 2) (c) 16 = 4 + 3(t + 2) (d) 4 + 5(p – 1) = 34 (e) 0 = 16 + 4(m – 6)

### NCERT Solutions for Class 7 Maths - Chapter 4 Exercise 4.3 Question 3

Solve the following equations. (a) 4 = 5(p – 2) (b) –4 = 5(p – 2) (c) 16 = 4 + 3(t + 2) (d) 4 + 5(p – 1) = 34 (e) 0 = 16 + 4(m – 6)

(a) p = 14/5, (b) p = 6/5 , (c) t = 2 , (d) p = 7, (e) m = 2