from a handpicked tutor in LIVE 1-to-1 classes

# Solve the following equations.

(a) 4 = 5(p – 2) (b) – 4 = 5(p – 2) (c) 16 = 4 + 3(t + 2)

(d) 4 + 5(p – 1) = 34 (e) 0 = 16 + 4(m – 6)

**Solution:**

We use the concepts of simple linear equations and fundamental operations like addition, subtraction, multiplication and division to solve the problem.

(a) 4 = 5(p - 2)

4 = 5p - 10

5p = 4 + 10

Therefore, p = 14/5

(b) - 4 = 5(p - 2)

- 4 = 5p - 10

- 4 + 10 = 5p

6 = 5p

Therefore, p = 6/5

(c) 16 = 4 + 3(t + 2)

16 = 4 + 3t + 6

16 - 10 = 3t

6 = 3t

t = 6/3 = 2

(d) 4 + 5(p - 1) = 34

4 + 5p - 5 = 34

5p - 1 = 34

5p = 35

p = 35/5

p = 7

(e) 0 = 16 + 4(m - 6)

0 = 16 + 4m - 24

8 = 4m

m = 8/4

m = 2

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 4

**Video Solution:**

## Solve the following equations. (a) 4 = 5(p – 2) (b) – 4 = 5(p – 2) (c) 16 = 4 + 3(t + 2) (d) 4 + 5(p – 1) = 34 (e) 0 = 16 + 4(m – 6)

NCERT Solutions for Class 7 Maths Chapter 4 Exercise 4.3 Question 3

**Summary:**

We have solved the following equations. (a) 4 = 5(p – 2); p = 14/5 (b) –4 = 5(p – 2; p = 6/5 ) (c) 16 = 4 + 3(t + 2); t = 2 (d) 4 + 5(p – 1) = 34 ; p = 7 (e) 0 = 16 + 4(m – 6); m = 2

**☛ Related Questions:**

- Solve The Following Equations A 2y 5 2 37 2 B 5t 28 10 C A 5 32 D Q 4 75 E 5 2 X 5 F 5 2 X 25 4
- Solve The Following Equations A 2x 4 12 B 3n 5 21 C 3n 5 21 D 4 2 X 8 E 42 X 8
- A Construct 3 Equations Starting With X 2 B Construct 3 Equations Starting With X 2
- Set Up Equations And Solve Them To Find The Unknown Numbers In The Following Cases A Add 4 To Eight Times A Number You Get 60 B One Fifth Of A Number Minus 4 Gives 3

visual curriculum