Consider the following frequency distribution of the heights of 60 students of a class:
Height (in cm) Number of students
150-155 15
155-160 13
160-165 10
165-170 8
170-175 9
175- 180 5
The sum of the lower limit of the modal class and upper limit of the median class is
a. 310
b. 315
c. 320
d. 330

Solution:

Given, the table represents the height and number of students.

We have to find the sum of the lower limit of the modal class and upper limit of the median class.

Height (in cm)	Number of students	Cumulative frequency
150-155	15	15
155-160	13	28
160-165	10	37
165-170	8	44
170-175	9	54
175-180	5	60

Modal class=class with maximum frequency

Maximum frequency = 15

So, modal class is 150 - 155

The lower limit of the modal class=150

From cumulative frequency, N = 60

Median = N/2

= 60/2

= 30

From the table,

The median class is 160 - 165

The upper limit of the median class is 165

Sum of the lower limit of the modal class and the upper limit of the median class=150 + 165

= 315

Therefore, the sum of the lower limit of the modal class and the upper limit of the median class is 315.

✦ Try This: Consider the following frequency distribution of the heights of 60 students of a class

Height (in cm)	Number of students
150-155	19
155-160	15
160-165	13
165-170	10
170-175	8
175-180	5

The sum of the lower limit of the modal class and upper limit of the median class is

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 14

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NCERT Exemplar Class 10 Maths Exercise 13.1 Sample Problem 3

Consider the following frequency distribution of the heights of 60 students of a class: Height (in cm) Number of students 150-155 15 155-160 13 160-165 10 165-170 8 170-175 9 175- 180 5. The sum of the lower limit of the modal class and upper limit of the median class is a. 310, b. 315, c. 320, d. 330

Summary:

The sum of the lower limit of the modal class and upper limit of the median class is 315

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