# Estimate each of the following using general rules:

(a) 730 + 998 (b) 796 - 314 (c) 12904 + 2888 (d) 28292 - 21496

Make ten more such examples of addition, subtraction, and estimation of their outcome

**Solution:**

We will be using the concept of estimation in math to solve this problem.

**(a)** 730 + 998

Nearest round off of 730 = 700

Nearest round off of 998 = 1000

Sum of 730 + 998 = 700 + 1000 = 1700

**(b)** 796 - 314

Nearest round off of 796 = 800

Nearest round off 314 = 300

Subtraction of 796 - 314 = 800 - 300 = 500

**(c)** 12904 + 2888

Nearest round off of 12904 = 13000

Nearest round off of 2888 = 3000

Sum of 12904 + 2888 = 13000 + 3000 = 16000

**(d)** 28292 - 21496

Nearest round off of 28292 = 28000

Nearest round off of 21496 = 21000

Subtraction of 28292 - 21496 = 28000 - 21000 = 7000

Ten more such examples are

(i) 435 + 282 = 400 + 300 = 700

(ii) 3986 + 5870 = 4000 + 6000 = 10000

(iii) 7392 - 4789 = 7000 - 5000 = 2000

(iv) 5160 - 2792 = 5000 - 3000 = 2000

(v) 2195 + 1306 = 2000 + 1000 = 3000

(vi) 1180 - 1382 = 1000 - 1000 = 0

(vii) 920 + 565 = 900 + 600 = 1500

(viii) 6410 - 4860 = 6000 - 5000 = 1000

(ix) 3841 + 1450 = 4000 + 1000 = 5000

(x) 6375 - 4229 = 6000 - 4000 = 2000

NCERT Solutions Class 6 Maths Chapter 1 Exercise 1.3 Question 1

## Estimate each of the following using general rule:(a) 730 + 998 (b) 796 - 314 (c) 12904 + 2888 (d) 28292 - 21496. Make ten more such examples of addition, subtraction and estimation of their outcome

**Summary:**

(a) 730 + 998 can be estimated as the sum of their nearest rounded off numbers such that, 700 + 1000 = 1700 (b) 796 - 314 can be estimated as the difference of their nearest rounded off numbers such that, 800 - 300 = 500 (c) 12904 + 2888 can be estimated as the sum of their nearest rounded off numbers such that, 13000 + 3000 = 16000 (d) 28292 - 21496 can be estimated as the difference of their nearest rounded off numbers such that, 28000 - 21000 = 7000.

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