# Estimate the following products using general rule:

(a) 578 × 161 (b) 5281 × 3491 (c) 1291 × 592 (d) 9250 × 29.

Make four more such examples.

**Solution:**

We will be using the concept of Estimation in Maths to solve this problem.

**(a)** 578 × 161

578 and 161 can be rounded off to 600 and 200

On rounding off both the numbers, we get 600 and 200

600 × 200 = 120000

**(b)** 5281 × 3491

5281 and 3491 can be rounded off to 5000 and 3500

On rounding off both the numbers, we get 5000 and 3500

5000 × 3500 = 17500000

**(c)** 1291 × 592

1291 and 592 can be rounded off to 1300 and 600

On rounding off both the numbers, we get 1300 and 600

1300 × 600 = 780000

**(d)** 9250 × 29

9250 and 29 can be rounded off to 9000 and 30

On rounding off both the numbers, we get 9000 and 30

9000 × 30 = 270000

**Examples:**

1) 123 × 41 can be approximated as 120 × 40 = 4800

2) 395 × 38 can be approximated as 400 × 40 = 16000

3) 521 × 31 can be approximated as 500 × 30 = 15000

4) 1234 × 19 can be approximated s 1200 × 20 = 24000

NCERT Solutions Class 6 Maths - Chapter 1 Exercise 1.3 Question 3

## Estimate the following products using general rule: (a) 578 × 161 (b) 5281 × 3491 (c) 1291 × 592 (d) 9250 × 29. Make four more such examples.

**Summary:**

(a) 578 × 161 can be estimated as 600 × 200 = 120000 (b) 5281 × 3491 can be estimated as 5000 × 3500 = 17500000 (c) 1291 × 592 can be estimated as 1300 × 600 = 780000 (d) 9250 × 29 can be estimated as 9000 × 30 = 270000.