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# Find the area of a quadrant of a circle whose circumference is 22 cm

**Solution:**

Let the radius of the circle be 'r'

Thus, the circumference C = 2πr

Therefore, r = C/2π

A quadrant of a circle means one of the four equal parts.

Therefore, the area of a quadrant = 1/4 × Area of a circle = 1/4 × πr^{2}

Circumference (C) = 22 cm

Therefore, radius (r) = C/2π

= 22/(2 × 22/7)

= (22 × 7)/(2 × 22)

= 7/2 cm

Therefore, the area of a quadrant = 1/4 × πr^{2}

= 1/4 × 22/7 × 7/2 × 7/2

= 77/8 cm^{2}

**☛ Check: **NCERT Solutions Class 10 Maths Chapter 12

**Video Solution:**

## Find the area of a quadrant of a circle whose circumference is 22 cm.

NCERT Solutions Class 10 Maths Chapter 12 Exercise 12.2 Question 2

**Summary:**

The area of a quadrant of a circle whose circumference is 22 cm is 77/8 cm^{2}.

**☛ Related Questions:**

- The length of the minute hand of a clock is 14 cm. Find the area swept by the minute hand in 5 minutes.
- A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding : (i) minor segment (ii) major sector. (Use π = 3.14)
- In a circle of radius 21 cm, an arc subtends an angle of 60° at the centre. Find:(i) the length of the arc(ii) area of the sector formed by the arc(iii) area of the segment formed by the corresponding chord
- A chord of a circle of radius 15 cm subtends an angle of 60° at the centre. Find the areas of the corresponding minor and major segments of the circle. (Use π = 3.14 and √3 = 1.73)

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