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# Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is ₹ 15/m^{2}. (Take π = 3.14)

**Solution:**

Diameter of the circular tabletop = 1.6 m

Radius of the circular tabletop = 1.6 m / 2 = 0.8 m

Area of circular tabletop = πr ^{2}

= 3.14 × 0.8 m × 0.8 m

= 2.0096 m^{2}

Since, the cost of 1m^{2} polishing = ₹ 15

The cost of polishing 2.0096 m^{2} = ₹ 15 × 2.0096

= ₹ 30.144

Thus, the cost of polishing a circular tabletop is ₹ 30.144.

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 11

**Video Solution:**

## Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is ₹ 15 m²

Class 7 Maths NCERT Solutions Chapter 11 Exercise 11.3 Question 8

**Summary:**

The cost of polishing a circular table-top of diameter 1.6 m is ₹ 30.14, if the rate of polishing is ₹ 15 m^{2}.

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