# From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet. (Take π = 22/7 )

**Solution:**

Radius of circular sheet (R) = 14 cm and radius of smaller circle (r) = 3.5 cm

Length of rectangle (l) = 3 cm and breadth of rectangle (b) = 1 cm

Area of the remaining sheet = Area of circular sheet – (Area of two smaller circle + Area of rectangle)

= πR^{2} – [2πr ^{2} + (length × Breadth)]

= 22/7 ×14 cm × 14 cm - [2 × 22/7 × 3.5 cm × 3.5 cm + (3 cm × 1 cm)]

= 22 × 2 cm × 14 cm - [44/7 × 3.5 cm × 3.5 cm + 3 cm]

= 616 cm^{2} - (77 + 3) cm^{2}

= (616 - 80) cm^{2}

= 536 cm^{2}

Therefore, the area of the remaining sheet is 536 cm^{2}.

**Video Solution:**

## From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet.

### Class 7 Maths NCERT Solutions - Chapter 11 Exercise 11.3 Question 10

**Summary:**

From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed, (as shown in the given figure below). The area of the remaining sheet is 536 cm^{2}.