From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet. (Take π = 22/7 )
Solution:
Radius of circular sheet (R) = 14 cm and radius of smaller circle (r) = 3.5 cm
Length of rectangle (l) = 3 cm and breadth of rectangle (b) = 1 cm
Area of the remaining sheet = Area of circular sheet – (Area of two smaller circle + Area of rectangle)
= πR2 – [2πr 2 + (length × Breadth)]
= 22/7 ×14 cm × 14 cm - [2 × 22/7 × 3.5 cm × 3.5 cm + (3 cm × 1 cm)]
= 22 × 2 cm × 14 cm - [44/7 × 3.5 cm × 3.5 cm + 3 cm]
= 616 cm2 - (77 + 3) cm2
= (616 - 80) cm2
= 536 cm2
Therefore, the area of the remaining sheet is 536 cm2.
☛ Check: Class 7 Maths NCERT Solutions Chapter 11
Video Solution:
From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet
Class 7 Maths NCERT Solutions Chapter 11 Exercise 11.3 Question 10
Summary:
From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed, (as shown in the given figure below). The area of the remaining sheet is 536 cm2.
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