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# A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path? (π = 3.14)

**Solution:**

Diameter of the circular flower bed = 66 m

Radius of circular flower bed (r) = 66/2 m = 33 m

Radius of circular flower bed with 4 m wide path (R) = 33 m + 4 m = 37 m

Area of path = Area of bigger circle – Area of smaller circle

= πR^{2} - πr^{2}

= π(R^{2} - r^{2} )

= 3.14 (37 m^{2} - 33 m^{2})

= 3.14 × (37 + 33) (37 – 33)

= 3.14 × 70 m^{ }× 4 m

= 879.20 m^{2}

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 11

**Video Solution:**

## A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path?

Maths NCERT Solutions Class 7 Chapter 11 Exercise 11.3 Question 13

**Summary:**

A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. The area of this path is 879.20 m^{2}.

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