Find the mean deviation about the median for the data
xi 15 21 27 30 35
fi 3 5 6 7 8
Solution:
The given observations are in ascending order.
Adding a column corresponding to cumulative frequencies of the given data,
we obtain the following table.
xi | fi | c. f |
15 | 3 | 3 |
21 | 5 | 8 |
27 | 6 | 14 |
30 | 7 | 21 |
35 | 8 | 29 |
Here, N = 29, which is odd.
Median = (29 + 1)/2 = 15th observation
This observation lies in the cumulative frequency 21, for which the corresponding observation is 30.
Therefore,
Median = 30
The absolute values of the deviations, |xi - M| are
|xi - M| | 15 | 9 | 3 | 0 | 5 |
fi | 3 | 5 | 6 | 7 | 8 |
|fi xi - M| | 45 | 45 | 18 | 0 | 40 |
Here, 5∑i = 1 fi = 29 and 5∑i = 1 fi|xi - M| = 148
M.D.(M) = 5∑i = 1 fi|xi - M|
= 1/29 × 148
= 5.1
NCERT Solutions Class 11 Maths Chapter 15 Exercise 15.1 Question 8
Find the mean deviation about the median for the data xi 15 21 27 30 35 fi 3 5 6 7 8
Summary:
The mean deviation about the median for the given data is 5.1
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