# Find the odd one out of the four options given below:

a. (-3, -6)

b. (+1, -10)

c. (-2, -7)

d. (-4, -9)

**Solution:**

Here we will use the rules of integers closed under addition and subtraction.

We have four individual pairs as given options, let us solve the pairs individually to observe the pattern. While solving the pairs we will use the rule of integers, (+) × (-) = -.

-3 + (-6) = -9

1 + (-10) = -9

-2 + (-7) = -9

-4 + (-9) = -13

From the given options the following pairs: (-3, -6), (+1, -10), (-2, -7) give the same answer on performing addition, whereas pair [-4 + (-9)] = -13, gives a different answer. So, the odd one out pair is -(4 + (-9).

**✦ Try This: **Find the odd one out of the four options in the following: (-2, 8),(4, 2),(-4, 3)

The given pairs can be solved by using the integers rules. On solving further using the addition rule, the pairs (-2, 8), (4, 2) give the same answer that is 6 whereas (-4, 3) gives a different answer that is -1. Hence the odd one out pair is (-4, 3)

**☛ Also Check:** NCERT Solutions for Class 7 Maths Chapter 1

**NCERT Exemplar Class 7 Maths Chapter 1 Solved Ex 9**

## Find the odd one out of the four options in the following: (-3, -6),(+1, -10),(-2, -7),(-4, -9)

**Summary:**

On solving the given pairs individually using the addition rule of integers, the pairs (-3, -6),(+1, -10),(-2, -7) give the same answer whereas -(4 + (-9) give the different answer. Hence, the odd one out pair is -(4 + (-9)

**☛ Related Questions:**

visual curriculum