# From a circular sheet of radius 4 cm, a circle of radius 3 cm is removed. Find the area of the remaining sheet. (Take π = 3.14)

**Solution:**

Radius of circular sheet (r₁) = 4 cm

Radius of removed circle (r₂) = 3 cm

Area of remaining sheet = Area of circular sheet – Area of removed circle = πr₁^{2} - πr₂^{2}

= π (r₁^{2} - r₂^{2})

= 3.14 (4^{2} - 3^{2}) cm^{2}

= 3.14 (16 - 9) cm^{2}

= 3.14 × 7 cm^{2}

= 21.98 cm^{2}

Thus, the area of the remaining sheet is 21.98 cm^{2}.

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 11

**Video Solution:**

## From a circular sheet of radius 4 cm, a circle of radius 3 cm is removed. Find the area of the remaining sheet.

Class 7 Maths NCERT Solutions Chapter 11 Exercise 11.3 Question 5

**Summary:**

From a circular sheet of radius 4 cm, a circle of radius 3 cm is removed. The area of the remaining sheet is 21.98 cm^{2}.

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