# If 2A7 ÷ A = 33, then find the value of A.

**Solution:**

When 2A7 is divided by A it gives 33. This also means that when 2A7 is divided by 33 it gives A.

Since 33 = 11 × 3

2A7 is divisible by 3 and 11.

Therefore

A = 2 + 7 = 9

And

2 + 9 + 7 = 18

Which is divisible by 3.

A = 9

**✦ Try This: **If 9A9B is divisible by 22 what are possible values of A and B.

If 9A9B is divisible by 22 implies that it is divisible by 11 and 2. Therefore,

9A9B is an __even number__ divisible by 11.

Since the number is divisible by 11

9 + 9 - (A + B) = 11

A + B = 7

Which implies that A and can assume the following values:

(a) A = 3, B = 4

(b) A = 4, B = 3

(c) A = 1,B = 6

(d) A = 6, B = 1

(e) A = 5, B = 2

(f) A = 2, B = 5

Since 9A9B is an even number alternatives (b), (d), and (f) are invalid

Therefore the possible values of A and B are,

A = 3, B = 4

A = 1, B = 6

A = 3, B = 4

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 16

**NCERT Exemplar Class 8 Maths Chapter 13 Problem 61**

## If 2A7 ÷ A = 33, then find the value of A.

**Summary:**

If 2A7 ÷ A = 33, then the value of A is 9.

**☛ Related Questions:**

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