# The table below shows the daily expenditure on food of 25 households in a locality

Find the mean daily expenditure on food by a suitable method

**Solution:**

To solve this question, we will use the step deviation method.

Mean, (x) = a + (Σf_{i}u_{i}/Σf_{i}) × h

We know that, Class mark, x_{i} = (Upper class limit + Lower class limit)/2

Class size, h = 50

Taking assumed mean, a = 225

Σf_{i} = 25 : From the table, we obtain

Σf_{i}u_{i} = -7

Mean, (x) = a + (Σf_{i}u_{i}/Σf_{i}) × h

= 225 + (- 7/25) × 50

= 225 - 14

= 211

Thus, the mean daily expenditure on food is ₹ 211.

**Video Solution:**

## The table below shows the daily expenditure on food of 25 households in a locality. Find the mean daily expenditure on food by a suitable method

### NCERT Solutions for Class 10 Maths - Chapter 14 Exercise 14.1 Question 6:

The table below shows the daily expenditure on food of 25 households in a locality. Find the mean daily expenditure on food by a suitable method

The mean daily expenditure on food of 25 households in a locality is ₹ 211