# Interpretation of |z1-z2|

Let \({z_1}\) and \({z_2}\) represent two fixed points in the complex plane. There is a very useful way to interpret the expression \(\left| {{z_1} - {z_2}} \right|\). Consider the following figure, which geometrically depicts the vector \({z_1} - {z_2}\):

However, observe that this vector is also equal to the vector drawn from the point \({z_2}\) to the point \({z_1}\):

Thus, \(\left| {{z_1} - {z_2}} \right|\) represents the length of the vector drawn from \({z_2}\) to \({z_1}\). In other words, \(\left| {{z_1} - {z_2}} \right|\) *represents the distance between the points* \({z_1}\) and \({z_2}\).

Let us take an example. Consider

\[\begin{align}&{z_1} = 1 + i\\&{z_2} = - 3i\end{align}\]

The expression \(\left| {{z_1} - {z_2}} \right|\), as we concluded, represents the distance between the points \({z_1}\) and \({z_2}\), which is \(\sqrt {17} \), as is evident from the following figure:

We can verify this algebraically:

\[\begin{align}&{z_1} - {z_2} = \left( {1 + i} \right) - \left( { - 3i} \right) = 1 + 4i\\&\Rightarrow \,\,\,{z_1} - {z_2} = \sqrt {1 + 16} = \sqrt {17} \end{align}\]

This interpretation of the expression \(\left| {{z_1} - {z_2}} \right|\) as the distance between the points \({z_1}\) and \({z_2}\) is extremely useful and powerful. Let us see how.

Suppose that *z* is a variable point in the complex plane such that \(\left| {z - i} \right| = 3\). What is the locus of *z*? In other words, what path does *z* trace out, while satisfying this constraint?

We can interpret \(\left| {z - i} \right|\) as the distance between the variable point *z* and the fixed point *i*. The equation \(\left| {z - i} \right| = 3\) says that the variable point *z* moves in such a way so that it is always at a constant distance of 3 units from the fixed point *i*. Thus, *z* traces out a circle in the plane, with center as the point *i* and radius 3 units:

Let’s take another example. Consider the equation

\[\left| {z - 1 + i} \right| = 2\]

We write this equation as

\[\left| {z - \left( {1 - i} \right)} \right| = 2\]

This says that the distance of *z* from the fixed point \(\left( {1 - i} \right)\) is always 2 units. Thus, *z* traces out a circle in the plane, with center as the point \(\left( {1 - i} \right)\) and radius equal to 2 units:

**Example 1:** *z* is a variable point in the plane such that

\[\left| {z - 2 + 3i} \right| = 11\]

Plot the locus of z.

**Solution:** We rewrite the given equation as

\[\left| {z - \left( {2 - 3i} \right)} \right| = 1\]

Thus, *z* traces out a circle of radius 1 unit, centered at the point \(\left( {2 - 3i} \right)\):

**Example 2:** A variable point *z* always satisfies

\(\left| {z - i} \right| = \left| {z + i} \right|\)

As z moves, what path will it trace out in the plane?

**Solution:** First, we rewrite the given equation as

\[\left| {z - i} \right| = \left| {z - \left( { - i} \right)} \right|\]

This equation says that the distance of *z* from the point \(i\) is equal to the distance of *z* from the point \(\left( { - i} \right)\). Thus, *z* lies on the perpendicular bisector of these two points:

Clealy, *z* can lie anywhere on the real axis.

**Example 3:** Plot the region in which *z* can lie, if it satisfied \(1 < \left| z \right| < 2\).

**Solution:** We can interpret \(\left| z \right|\) or \(\left| {z - 0} \right|\) as the distance between the point *z* and the origin. The given inequality says that the distance of the point *z* from the origin is greater than 1 but less than 2. Thus, *z* can lie anywhere in the following ring-shaped region:

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