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# A tackle box is a rectangular solid with sides of 15 in., 12 in., and 9 in. What is its volume?

**Solution:**

The volume of the rectangular solid is given by,

V = length × breadth × height

Here,

length = 15 in,

breadth = 12 in,

and height = 9 in

Therefore,

Volume V = 15 × 12 × 9

V = 1620 in^{3}

**Hence, the required volume is 1620 cubic inches.**

## A tackle box is a rectangular solid with sides of 15 in., 12 in., and 9 in. What is its volume?

**Summary: **

The volume of a tackle box, which is a rectangular solid with sides of 15 in, 12 in, and 9 in is 1620 in^{3}.

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