What is the axis of symmetry and vertex for the function f(x) = 3(x - 2)2 + 4?
Solution:
Given f(x) = 3(x - 2)2 + 4
The graph will be symmetrical to the y-axis and since a> 0, the parabola opens up.
The axis of symmetry is the line that divides a parabola into two symmetrical parts. The vertex is the point where the axis of symmetry intersects the parabola.
The axis of the symmetry is x = 2
The vertex form of a parabola is y = a (x - h)2 + k
The vertex is given by (h,k) coordinates.
In order to find the vertex, we need to compare the given equation to the vertex form of the parabola.
f(x) = 3(x - 2)2 + 4=0
a = 3, h = 2 and k = 4
Thus the vertex of the function is (2,4)
What is the axis of symmetry and vertex for the function f(x) = 3(x - 2)2 + 4?
Summary:
The axis of symmetry is y-axis and vertex for the function f(x) = 3(x - 2)2 + 4 is (2 ,4).
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