Which is a factor of 6x³y + 6xy - 12x² - 12?
x + 2, xy - 1, x² + 1, x² - 2

Solution:

Given expression is

6x³y + 6xy - 12x² - 12

Take the terms common

= 6xy(x² + 1) - 12(x² + 1)

= (x² + 1)(6xy - 12)

= 6(x² + 1)(xy - 2)

Therefore, x² + 1 is one of the two factors of 6x³y + 6xy - 12x² - 12.

Which is a factor of 6x³y + 6xy - 12x² - 12?

Summary:

x² + 1 is the factor of 6x³y + 6xy - 12x² - 12.