Which of the following is not a way to represent the solution of the inequality: 2(x + 1) ≥ 20?
x ≥ 9
x ≤ 9
A number line with a closed circle on 9 and shading to the left.
A number line with a closed circle on 9 and shading to the right. 

Solution:

Given: Inequality is 2(x + 1) ≥ 20

Let us solve for x

2x + 2 ≥ 20

By subtracting 2 on both sides

2x + 2 - 2 ≥ 20 - 2

2x ≥ 18

Now divide by 2 both sides

x ≥ 9

It is equivalent to 9 ≤ x

The solution is [9,∞)

All the real numbers are greater than or equal to 9. A number line with a closed circle on 9 and shading to the right.

Therefore, the solution of the inequality cannot be represented as x ≤ 9 and a number line with a closed circle on 9 and shading to the left.

Which of the following is not a way to represent the solution of the inequality: 2(x + 1) ≥ 20?

Summary:

The solution of the inequality 2(x + 1) ≥ 20 cannot be represented as x ≤ 9 and a number line with a closed circle on 9 and shading to the left.