A die is thrown 1000 times and the outcomes were recorded as follows :
Outcome 1 2 3 4 5 6
Frequency 180 150 160 170 150 190
If the die is thrown once more, then the probability that it shows 5 is :
a. 9/50
b. 3/20
c. 4/25
d. 7/25

Solution:

It is given that

A die is thrown 1000 times

Here

Probability showing 5 is P(E) = Number of times 5 occurs/ Total number of throws

Substituting the values

P(E) = 150/1000

So we get

P(E) = 3/20

Therefore, the probability that it shows 5 is 3/20.

✦ Try This: A die is thrown 1000 times and the outcomes were recorded as follows :

Outcome	1	2	3	4	5	6
Frequency	120	130	140	150	160	170

If the die is thrown once more, then the probability that it shows 4 is :

It is given that

A die is thrown 1000 times

Here

Probability showing 4 is P(E) = Number of times 4 occurs/ Total number of throws

Substituting the values

P(E) = 150/1000

So we get

P(E) = 3/20

Therefore, the probability that it shows 5 is 3/20.

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 14

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NCERT Exemplar Class 9 Maths Exercise 14.1 Sample Problem 3

A die is thrown 1000 times and the outcomes were recorded as follows : Outcome 1 2 3 4 5 6 Frequency 180 150 160 170 150 190. If the die is thrown once more, then the probability that it shows 5 is : a. 9/50, b. 3/20, c. 4/25, d. 7/25

Summary:

A die is thrown 1000 times and the outcomes are recorded. If the die is thrown once more, then the probability that it shows 5 is 3/20

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