# Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.

**Solution:**

We use the basic rules of construction to solve the question given. We will use scale and compass to do the construction required.

To construct a ΔDEF, first, we draw a rough sketch with the given measure such that DE = 5cm, DF = 3cm and ∠EDF = 90° for our reference, then follow the steps given below.

**Steps of construction :**

- Draw a line segment DE of length 5 cm.
- At D, draw a ray DX making 90° with DE.
- With D as the center, draw an arc of radius 3cm to cut DX at point F.
- Join EF to get the required triangle.
- Thus, ΔDEF is the required triangle.

**Video Solution:**

## Construct ∆DEF such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.

### Class 7 Maths NCERT Solutions - Chapter 10 Exercise 10.3 Question 1

**Summary:**

∆DEF is constructed such that DE = 5 cm, DF = 3 cm and m∠EDF = 90°.