# Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°.

**Solution:**

We use the basic rules of construction to solve the question given.

To construct a ΔABC first, we draw a rough sketch with the given measure such that BC = 7.5 cm, AC = 5 cm, and ∠C = 60° for our reference, then follow the steps given below.

**Steps of construction :**

- Draw a line segment BC of length 7.5 cm.
- At C, draw a ray CX making 60° with BC.
- With C as the center, draw an arc of radius 5 cm to cut CX at point A.
- Join AB to get the required triangle.
- Thus, ΔABC is the required triangle.

**Video Solution:**

## Construct ∆ABC with BC = 7.5 cm, AC = 5 cm and m∠C = 60°.

### Class 7 Maths NCERT Solutions - Chapter 10 Exercise 10.3 Question 3

**Summary:**

∆ABC is constructed with BC = 7.5 cm, AC = 5 cm and m∠C = 60°