# Construct ∆ABC, given m∠A = 60°, m∠B = 30° and AB = 5.8 cm.

**Solution:**

We use the basic rules of construction to solve the question given. We will use scale and compass to do the construction required.

We can draw a rough sketch of ΔABC with the given measure for reference. This will help us in deciding how to proceed. Then follow the steps given below.

**Steps of construction :**

- Draw a line segment AB of length 5.8 cm.
- At A, draw ray AY making 60° with AB.
- At B, draw ray BX making 30° with AB.
- Rays BX and AY will intersect at point C.
- Triangle ABC is now constructed.

**Video Solution:**

## Construct ∆ABC, given m∠A = 60°, m∠B = 30° and AB = 5.8 cm.

### Class 7 Maths NCERT Solutions - Chapter 10 Exercise 10.4 Question 1

**Summary:**

∆ABC is constructed with m∠A = 60°, m∠B = 30° and AB = 5.8 cm.