# Draw a line segment of length 7.6 cm and divide it in the ratio 5:8. Measure the two parts

**Solution:**

- Draw the line segment of the given length.
- Then draw another line that makes an acute angle with the given line.
- Divide the line into m + n parts where m and n are the ratios given.
- The basic proportionality theorem states that “If a straight line is drawn parallel to a side of a triangle, then it divides the other two sides proportionally".

Steps of construction:

- Draw AB = 7.6 cm
- Draw ray AX, making an acute angle with AB
- Mark 13 (5 + 8) points A
_{1}, A_{2},….A_{13}on AX such that AA_{1}= A_{1}A_{2}= A_{2}A_{3}=...... A_{12}A_{13} - Join BA
_{13} - Through A
_{5}(since we need 5 parts to 8 parts) draw CA_{5}parallel to BA_{13}where C lies on AB.

Now AC: CB = 5 : 8

We find AC = 2.9 cm and CB = 4.7 cm

Proof:

CA_{5} is parallel to BA_{13}

By Basic Proportionality theorem, in ΔAA_{13}B

AC/BC = AA_{5}/A_{5}A_{13} = 5/8 (By Construction)

Thus, C divides AB in the ratio 5:8.

**Video Solution:**

## Draw a line segment of length 7.6 cm and divide it in the ratio 5:8. Measure the two parts

### NCERT Solutions Class 10 Maths - Chapter 11 Exercise 11.1 Question 1:

Draw a line segment of length 7.6 cm and divide it in the ratio 5:8. Measure the two parts

Point C divides the line segment AB of length 7.6 cm in the ratio of 5:8