# Express each of the following numbers using exponential notation:

(i) 512 (ii) 343 (iii) 729 (iv) 3125

**Solution:**

(i) 512

Let's prime factorize the number 512.

The factors of 512 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2

Base = 2 and exponent = 9

So, exponential form is 2^{9}

(ii) 343

Let's prime factorize the number 343.

The factors of 343 = 7 × 7 × 7

Base = 7 and exponent = 3

So, exponential form is = 7^{3}

(iv) 729

Let's prime factorize the number 729.

The factors of 729 = 3 × 3 × 3 × 3 × 3 × 3

Base = 3 and exponent = 6

So, exponential form 3^{6}

(v) 3125

Let's prime factorize the number 3125.

The factors of 3125 = 5 × 5 × 5 × 5 × 5

Base = 5 and exponent = 5

So, exponential form 5^{5}

**Video Solution:**

## Express each of the following numbers using exponential notation: (i) 512 (ii) 343 (iii) 729 (iv) 3125

### Maths NCERT Solutions Class 7 - Chapter 13 Exercise 13.1 Question 3

**Summary:**

Expressing each of the following numbers using exponential notation:(i) 512 = 2^{9 }(ii) 343 = 7^{3 }(iii) 729 = 3^{6 }(iv) 3125 = 5^{5}