The coach of a cricket team buys 3 bats and 6 balls for ₹ 3900. Later, she buys another bat and 3 more balls of the same kind for ₹ 1300. Represent this situation algebraically and geometrically
Solution:
(i) Three bats and six balls for ₹ 3900
(ii) One bat and three balls for ₹ 1300
Assuming the cost of one bat as ₹ x and the cost of one ball as ₹y. Two linear equations can be formed for the above situation.
The cost of 3 bats and 6 balls is ₹ 3900. Mathematically:
3x + 6y = 3900
Also, the cost of 1 bat and 3 balls is ₹ 1300. Mathematically:
x + 3y = 1300
Algebraic representation where x and y are cost of bat and ball respectively.
3x + 6y = 3900 ---(1)
x + 3y = 1300 ---(2)
Therefore, the algebraic representation for equation (1) is: 3x + 6y = 3900
And, the algebraic representation for equation 2 is: x + 3y = 1300
Let us represent these equations graphically. For this, we need at least two solutions for each equation. We give these solutions in table shown below.
x |
300 |
900 |
y |
500 |
200 |
x |
100 |
400 |
y |
400 |
300 |
The graphical representation is as follows.
Unit: 1cm = ₹ 100.
The graphical representation of system of linear equations is identical lines.
Video Solution:
The coach of a cricket team buys 3 bats and 6 balls for ₹ 3900. Later, she buys another bat and 3 more balls of the same kind for ₹ 1300. Represent this situation algebraically and geometrically.
NCERT Solutions Class 10 Maths Chapter 3 Exercise 3.1 Question 2 - Chapter 3 Exercise 1.1 Question 2:
Summary:
The coach of a cricket team buys 3 bats and 6 balls for ₹ 3900. Later, she buys another bat and 3 more balls of the same kind for ₹ 1300. This situation is algebraically and geometrically represented. The graphical representation of system of linear equations is identical lines.