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# The cost of 2 kg of apples and 1 kg of grapes on a day was found to be ₹ 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is ₹ 300. Represent the situation algebraically and geometrically

**Solution:**

(i) The cost of 2 kg of apples and 1 kg of grapes is ₹ 160

(ii) The cost of 4 kg of apples and 2 kg of grapes is ₹ 300

Let, the cost of 1 kg apples = ₹ x

The cost of 1 kg grapes = ₹ y

The two linear equations can be formed for the above situation.

Cost kg 2 kg apples and 1 kg of grapes are ₹ 160. Mathematically it can be represented as,

2x + y = 160 --- Equation(1)

Also, cost of 4 kg apples and 2 kg of grapes are ₹ 300. Mathematicallyit can be represented as,

4x + 2y = 300

2(2x + y) = 300

2x + y = 150 --- Equation(2)

Therefore, the algebraic representation for equation(1) is:

2x + y = 160

y = 160 - 2x

And, the algebraic representation for equation(2) is:

2x + y = 150

y = 150 - 2x

For the representation of these equations graphically, we need at least two solutions for each equation. Let's tabulate the solutions as shown below.

The graphical representation is as follows:

x-axis: 1 unit = ₹10, y-axis: 1 unit = ₹10

Since the lines are parallel, hence there is no solution.

**☛ Check: **NCERT Solutions for Class 10 Maths Chapter 3

**Video Solution:**

## The cost of 2 kg of apples and 1 kg of grapes on a day was found to be ₹ 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is ₹ 300. Represent the situation algebraically and geometrically

NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.1 Question 3

**Summary:**

The cost of 2 kg of apples and 1 kg of grapes on a day was found to be ₹ 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is ₹300. The situation is represented algebraically and geometrically. On representing the solution graphically the lines are found to be parallel and hence, no solution

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