# The cost of 2 kg of apples and 1 kg of grapes on a day was found to be ₹ 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is ₹ 300. Represent the situation algebraically and geometrically

**Solution:**

(i) The cost of 2 kg of apples and 1 kg of grapes is ₹ 160

(ii) The cost of 4 kg of apples and 2 kg of grapes is ₹ 300

Let, the cost of 1 kg apples = ₹ x

The cost of 1 kg grapes = ₹ y

The two linear equations can be formed for the above situation.

Cost kg 2 kg apples and 1 kg of grapes are ₹ 160. Mathematically,

2x + y = 160 --- Equation(1)

Also, cost kg 4 kg apples and 2 kg of grapes are ₹ 300. Mathematically,

4x + 2y = 300

2(2x + y) = 300

2x + y = 150 --- Equation(2)

Therefore, the algebraic representation is for equation(1) is:

2x + y = 160

y = 160 - 2x

And, the algebraic representation is for equation(2) is:

2x + y = 150

y = 150 - 2x

Representation of these equations graphically. For this, we need at least two solutions for each equation. We give these solutions in the table shown below.

The graphical representation is as follows:

1 Unit = 1 cm = ₹ 10

Since the lines are parallel hence no solution.

**Video Solution:**

## The cost of 2 kg of apples and 1 kg of grapes on a day was found to be ₹ 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is ₹ 300. Represent the situation algebraically and geometrically

### NCERT Solutions for Class 10 Maths - Chapter 3 Exercise 3.1 Question 3:

The cost of 2 kg of apples and 1 kg of grapes on a day was found to be ₹ 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is ₹ 300. Represent the situation algebraically and geometrically

Since the cost of 2 kg of apples and 1 kg of grapes on a day was found to be ₹ 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is ₹ 300. Upon representing the solution graphically the lines are parallel hence no solution