ABCD is a rhombus. AC = 8 cm, and BD = 3.5 cm. What is the area of the rhombus?
Solution:
Given, ABCD is a rhombus.
AC = 8cm
BD = 3.5cm
We have to find the area of the rhombus.
AC and BD are the diagonals of the rhombus
Area of the rhombus = (d1 × d2) / 2
Where, d1 and d2 are the diagonals of the rhombus
Area = (8)(3.5) / 2
= 4(3.5)
= 14cm2
Therefore, area of the rhombus is 14cm2.
ABCD is a rhombus. AC = 8 cm, and BD = 3.5 cm. What is the area of the rhombus?
Summary:
ABCD is a rhombus. AC = 8 cm, and BD = 3.5 cm. The area of the rhombus is 14cm2.
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