If p(a) = 0.38, p(b) = 0.83, and p(a ∩ b) = 0.24; then p(a ∪ b) =

Solution:

Suppose we have two sets A and B.

Now, A U B consists of elements of both sets A and B, taken one at a time.

We have the following representations:

n(A U B) = Number of elements in A U B

n(A) = Number of elements in A

n(B) = Number of elements in B

n(A ∩ B) = Number of elements that are common to both A and B

Given, p(a) = 0.38

p(b) = 0.83

p(a∩b) = 0.24

We have to find p(a∪b)

P(a∩b) = P(a) + P(b) - P(a∪b)

0.24 = 0.38 + 0.83 - P(a∪b)

0.24 = 1.21 - P(a∪b)

P(a∪b) = 1.21 - 0.24

P(a∪b) = 0.97

Therefore, the value of p(a∪b) is 0.97.

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If p(a) = 0.38, p(b) = 0.83, and p(a ∩ b) = 0.24; then p(a ∪ b) =

Summary:

 If p(a) = 0.38, p(b) = 0.83, and p(a ∩ b) = 0.24; then p(a ∪ b) = 0.97.