# The equation of the circle whose center is at (2, 1) and radius is 3 is?

The standard equation of circle is (x − h)^{2} + (y − k)^{2} = r^{2}. Let us use this to find the answer.

## Answer: The equation of the circle whose center is at (2, 1) and radius is 3 is (x - 2)^{2} + (y - 1)^{2} = 9.

Let's solve it step by step.

**Explanation:**

Given that, center (h, k) = (2, 1) and radius (r) = 3.

The equation of a circle with center (h, k) and radius (r) is (x − h)^{2} + (y − k)^{2} = r^{2}

Substitute the values of h, k, r.

(x − 2)^{2} + (y − 1)^{2} = 3^{2}

(x - 2)^{2} + (y - 1)^{2} = 9

You can use Cuemath's Equation of Circle Calculator to verify the answer.