# What is the range of f(x) = 3x + 9 given x > 0?

{y | y < 9}, {y | y > 9}, {y | y > 3}, {y | y < 3}

**Solution:**

Given function f(x) = 3x + 9 and the domain(value of x) of x is x>0

f(x) = 3x + 9

Put x = 1

f(1) = 3(1) + 9

f(1) = 3 + 9 = 12

Putx = 2

f(2) = 3(2) + 9

f(2) = 6 + 9 = 15

The value of f(x) is increasing for every increasing value of x

Therefore the range will be y > 9

## What is the range of f(x) = 3x + 9 given x > 0?

**Summary:**

The range of the function f(x) = 3x + 9 will be {y | y > 9}