# What is the range of f(x) = 3x + 9 given x > 0?

{y | y < 9}, {y | y > 9}, {y | y > 3}, {y | y < 3}

**Solution:**

**The range of a function in algebra is the set of all its outputs.**

Given:

function f(x) = 3x + 9 and the domain (value of x) of x is x > 0.

**Let us substitute the value of x greater than 0 and observe the result.**

f(x) = 3x + 9

**Put x = 1**

f(1) = 3(1) + 9

f(1) = 3 + 9 = 12

**Put x = 2**

f(2) = 3(2) + 9

f(2) = 6 + 9 = 15

**The value of f(x) is increasing for every increasing value of x**

**Therefore the range will be y > 9**

## What is the range of f(x) = 3x + 9 given x > 0?

**Summary:**

The range of the function f(x) = 3x + 9 will be {y | y > 9}

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