Cramers Rule
Cramer's rule is invented by mathematician Gabriel Cramer in 1750s. This rule is used to find the solution of a system of equations with any number of variables and the same number of equations. Sometimes, when we are solving a system of equations in 3 variables, say x, y, and z, we may need to solve for two variables x and y to solve for variable z. But using Cramer's rule, we can find the value of any variable without finding the values of the other variables.
But this rule has some limitations with respect to the solutions. This rule can be applied only when the system has unique solutions. But how do we know when a system has unique solution? Let us learn more about this along with the definition and formula of Cramer's Rule.
1. | What is Cramer's Rule? |
2. | Cramer's Rule Formula |
3. | Cramer's Rule For 2 x 2 |
4. | Cramer's Rule For 3 x 3 |
5. | Cramer's Rule Chart |
6. | FAQs on Cramer's Rule |
What is Cramer's Rule?
Cramer's rule is one of the methods used to solve a system of equations. This rule involves determinants. i.e., the values of the variables in the system are found with the help of determinants. Let us consider a system of equations in n variables x₁, x₂, x₃, ..., xₙ written in the matrix form AX = B, where
- A = the coefficient matrix which is a square matrix
- X = the column matrix with variables
- B = the column matrix with the constants (which are on the right side of the equations)
Cramer's Rule Formula
Here is the Cramer's rule formula to solve the system AX = B (or) to find the values of the variables x₁, x₂, x₃, ..., xₙ. To solve the system of equations:
- Find det |A| and represent it by D.
- Find the determinants Dₓ₁, Dₓ₂, Dₓ₃, ..., Dₓₙ, where Dₓᵢ is the determinant of matrix A where the ith column is replaced by the column matrix B.
- We divide each of these determinants by D to find the value of the corresponding variables. i.e.,
x₁ = Dₓ₁/D, x₂ = Dₓ₂/D, ...., xₙ = Dₓₙ/D.
Note that the system of equations has a unique solution only when D ≠ 0.
Are you getting confused with this general formula of Cramer's rule? Let us see this rule for 2 x 2 and 3 x 3 system of equations for clarification.
Cramer's Rule For 2 x 2
Using the above formula, let us see how to solve a system of 2 equations in 2 variables using Cramer's rule. Here are the steps to solve this system of 2x2 equations using Cramer's rule.
- Step-1: Write this system in matrix form is AX = B.
- Step-2: Find D which is the determinant of A. Also, find the determinants Dₓ and Dᵧ where
Dₓ = det (A) where the first column is replaced with B
Dᵧ = det (A) where the second column is replaced with B - Step-3: Find the values of the variables x and y by dividing each of Dₓ and Dᵧ by D respectively.
Consider a system of two equations in two variables x and y.
a₁x + b₁y = c₁ and
a₂x + b₂y = c₂
Let us apply the above steps to solve the above system.
Step-1: Write this system in matrix form is AX = B, where
- A = \(\left[\begin{array}{ll}a_{1} & b_{1} \\ \\ a_{2} & b_{2}\end{array}\right]\) = the coefficient matrix
- X = \(\left[\begin{array}{l}x \\ \\ y\end{array}\right]\) = the variable matrix
- B = \(\left[\begin{array}{l}c_1 \\ \\ c_2\end{array}\right]\) = the constant matrix
Step-2: Find D which is the determinant of A. i.e., D = det (A) = \(\left|\begin{array}{ll}a_{1} & b_{1} \\ \\ a_{2} & b_{2}\end{array}\right|\). Also, find the determinants Dₓ and Dᵧ where
- Dₓ = det (A) where the first column is replaced with B = \(\left|\begin{array}{ll}c_{1} & b_{1} \\ \\ c_{2} & b_{2}\end{array}\right|\)
- Dᵧ = det (A) where the second column is replaced with B = \(\left|\begin{array}{ll}a_{1} & c_{1} \\ \\ a_{2} & c_{2}\end{array}\right|\)
Step-3: Find the values of the variables x and y (when D ≠ 0) using
- x = Dₓ/D
- y = Dᵧ/D
Cramer's Rule For 3 x 3
We will just extend the same process of Cramer's rule for 2 equations for a 3x3 system of equations as well. Here are the steps to solve this system of 3x3 equations using Cramer's rule.
- Step-1: Write this system in matrix form is AX = B.
-
Step-2: Find D which is the determinant of A. i.e., D = det (A). Also, find the determinants Dₓ, Dᵧ, and D\(_z\) where
Dₓ = det (A) where the first column is replaced with B
Dᵧ = det (A) where the second column is replaced with B
D\(_z\) = det (A) where the third column is replaced with B -
Step-3: Find the values of the variables x, y, and z by dividing each of Dₓ, Dᵧ, and D\(_z\) by D respectively.
Consider a system of three equations in three variables x, y, and z.
a₁x + b₁y + c₁z = d₁
a₂x + b₂y + c₂z = d₂ and
a₃x + b₃y + c₃z = d₃
Let us apply the above steps to solve 3x3 equations.
Step-1: Write this system in matrix form is AX = B, where
- A = \(\left[\begin{array}{ll}a_{1} & b_{1} &c_1\\ a_{2} & b_{2}&c_2\\a_3&b_3&c_3\end{array}\right]\) = the coefficient matrix
- X = \(\left[\begin{array}{l}x \\ y \\z\end{array}\right]\) = the variable matrix
- B = \(\left[\begin{array}{l}d_1 \\ d_2 \\d_3\end{array}\right]\) = the constant matrix
Step-2: Find D which is the determinant of A. i.e., D = det (A) = \(\left|\begin{array}{ll}a_{1} & b_{1} &c_1\\ a_{2} & b_{2}&c_2\\a_3&b_3&c_3\end{array}\right|\). Also, find the determinants Dₓ, Dᵧ, and D\(_z\) where
- Dₓ = det (A) where the first column is replaced with B = \(\left|\begin{array}{ll}d_{1} & b_{1} &c_1\\ d_{2} & b_{2}&c_2\\d_3&b_3&c_3\end{array}\right|\)
- Dᵧ = det (A) where the second column is replaced with B = \(\left|\begin{array}{ll}a_{1} & d_{1} &c_1\\ a_{2} & d_{2}&c_2\\a_3&d_3&c_3\end{array}\right|\)
- D\(_z\) = det (A) where the third column is replaced with B = \(\left|\begin{array}{ll}a_{1} & b_{1} &d_1\\ a_{2} & b_{2}&d_2\\a_3&b_3&d_3\end{array}\right|\)
Step-3: Find the values of the variables x, y, and z (when D ≠ 0)using
- x = Dₓ/D
- y = Dᵧ/D
- z = D\(_z\)/D
Cramer's Rule Chart
If we observe the formula of Cramer's rule in all the above three sections, we have mentioned that D ≠ 0 everywhere. This is because while finding the values of the variables, D is in the denominator and if D = 0, the fraction (the value of the variable) goes undefined. So this rule is applicable only when D ≠ 0. But what about the system of equations when D = 0? Then there are two possibilities.
- The system may have no solution.
- The system may have an infinite number of solutions.
Though Cramer's rule doesn't help in finding the infinite number of solutions, we can determine whether the system has "no solution" or "infinite number of solutions" using the determinants which we compute as the process of applying the rule.
- If D ≠ 0, we say that the system AX = B has unique solution.
- If D = 0 and atleast one of the numerator determinants is a 0, then the system has infinitely many solutions.
- If D = 0 and none of the numerator determinants is 0, then the system has no solution.
You can visualize this from the following Cramer's rule chart.
Important Notes on Cramer's Rule:
Here are some important notes related to the application of Cramer's rule:
- If there are n variables and n equations, we have to compute (n + 1) determinants.
- This rule can give the solutions only when D ≠ 0.
- If D = 0, the system has either an infinite number of solutions or no solutions.
- We cannot find solutions by using this rule when the system has an infinite number of solutions.
Related Topics:
Cramer's Rule Examples
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Example 1: Solve the following system of 2x2 equations: x + y = 5 and 2x - 3y = -4.
Solution:
The given system can be written in the matrix form AX = B where, A = \(\left[\begin{array}{ll}1 & 1 \\ \\ 2 & -3\end{array}\right]\), X = \(\left[\begin{array}{l}x \\ \\ y\end{array}\right]\), and B = \(\left[\begin{array}{l}5 \\ \\ -4\end{array}\right]\).
Now, we will find the determinants.
D = det(A) = \(\left|\begin{array}{ll}1 & 1 \\ \\ 2 & -3\end{array}\right|\) = 1(-3) - 1(2) = -3 - 2 = -5.
Dₓ = \(\left|\begin{array}{ll}5 & 1 \\ \\ -4 & -3\end{array}\right|\) = 5(-3) - 1(-4) = -15 + 4 = -11.
Dᵧ = \(\left[\begin{array}{ll}1 & 5 \\ \\ 2 & -4\end{array}\right]\) = 1(-4) - 5(2) = -4-10 = -14.
Now, by Cramer's rule for 2 equations,
x = Dₓ/D = (-11) / (-5) = 11/5
y = Dᵧ/D = (-14) / (-5) = 14/5Answer: The solution of the given system is, x = 11/5 and y = 14/5.
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Example 2: Solve the following system of 3 equations in 3 variables using Cramer's rule: x + y + z = 2, 2x + y + 3z = 9, and x - 3y + z = 10.
Solution:
The given system can be written in the matrix form AX = B where, A = \(\left[\begin{array}{ll}1 & 1 & 1 \\ 2 & 1&3\\1&-3&1\end{array}\right]\), X = \(\left[\begin{array}{l}x \\ y\\z\end{array}\right]\), and B = \(\left[\begin{array}{l}2 \\ 9\\10 \end{array}\right]\).
Now, we will find the determinants.
D = det(A) = \(\left|\begin{array}{ll}1 & 1 & 1 \\ 2 & 1&3\\1&-3&1\end{array}\right|\)
= 1(1 + 9) - 1(2 - 3) + 1(-6 - 1)
= 10 + 1 - 7
= 4
Dₓ = \(\left|\begin{array}{ll}2 & 1 & 1 \\ 9 & 1&3\\10 &-3&1\end{array}\right|\)
= 2(1 + 9) - 1(9 - 30) + 1(-27 - 10)
= 20 + 21 - 37
= 4
Dᵧ = \(\left|\begin{array}{ll}1 & 2 & 1 \\ 2 & 9&3\\1&10&1\end{array}\right|\)
= 1(9 - 30) - 2(2 - 3) + 1(20 - 9)
= -21 + 2 + 11
= - 8
D\(_z\) = \(\left|\begin{array}{ll}1 & 1 & 2 \\ 2 & 1&9\\1&-3&10\end{array}\right|\)
= 1(10 + 27) - 1(20 - 9) + 2(-6 - 1)
= 37 - 11 - 14
= 12
Now, we apply the formulas:
x = Dₓ/D = 4/4 = 1
y = Dᵧ/D = -8/4 = -2
z = D\(_z\) = 12/4 = 3Answer: The solution of the given system is x = 1, y = -2, and z = 3.
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Example 3: Determine whether the following system has unique solution, infinite number of solutions, or no solution: x - 2y + 3z = 17, 2x + y + 2z = 6, and 2x - 4y + 6z = 34.
Solution:
The given system can be written in the matrix form AX = B where, A = \(\left[\begin{array}{ll}1 & -2 & 3 \\ 2 & 1&2\\2&-4&6\end{array}\right]\), X = \(\left[\begin{array}{l}x \\ y\\z\end{array}\right]\), and B = \(\left[\begin{array}{l}17 \\ 6\\34 \end{array}\right]\).
Now, we will find the determinants.
D = det(A) = \(\left|\begin{array}{ll}1 & -2 & 3 \\ 2 & 1&2\\2&-4&6\end{array}\right|\)
= 1(6 + 8) + 2 (12 - 4) + 3(-8 - 2)
= 14 + 16 - 30
= 0
Dₓ = \(\left|\begin{array}{ll}17 & -2 & 3 \\ 6 & 1&2\\34&-4&6\end{array}\right|\)
= 17(6 + 8) + 2(36 - 68) + 3(-24 - 34)
= 238 - 64 - 174
= 0
Here, D = 0, and one of Dₓ, Dᵧ, and D\(_z\) is 0.
By Cramer's rule, the system has infinitely many solutions.
Answer: The given system has infinitely many solutions.
FAQs on Cramer's Rule
How Does Cramer's Rule Work?
Cramer's rule is used to find the solution of the system of equations with a unique solution. It is also used to find whether the system has a unique solution, no solution, or an infinite number of solutions.
Who Invented Cramer's Rule of Matrices?
Cramer's rule for matrices is invented by a mathematician called Gabriel Cramer in 1750.
What is Cramer's Rule 2x2?
First, write the given system of 2x2 equations as AX = B, where X is a column matrix of the variables x and y. Then find the determinants D, Dₓ, and Dᵧ, where D = det(A) and Dₓ and Dᵧ are same as det(A) where the first and second columns are respectively replaced by the matrix B. Then use the following to find the variables x and y.
- x = Dₓ/D
- y = Dᵧ/D
How Do You Use Cramer's Rule for 2x3 Equations?
Cramer's rule deals with the determinants and determinants can be found only for square matrices. But if we write 2x3 equations in the form of AX = B, then A is NOT a square matrix (it is a rectangular matrix) and hence this rule cannot be applied in this case.
What is Dₓ in Cramer's Rule?
To solve a system of equations using Cramer's Rule, first, we write it in the form AX = B. Then Dₓ is a Cramer's rule determinant of the coefficient matrix where the first column is replaced with the column matrix B.
What are the Advantages of Cramer's Rule?
Cramer's rule is used to solve the system of equations where the number of variables is equal to the number of equations. Also, using this rule, we can find the value of finding any variable right away without finding the other variables.
What is Cramer's Rule 3x3?
First, write the given system of 3x3 equations as AX = B, where X is a column matrix of the variables x, y, and z. Then find the determinants D, Dₓ, Dᵧ, and D\(_z\), where D = det(A) and Dₓ, Dᵧ, and D\(_z\) are same as det(A) where the first, second, and third columns are respectively replaced by the matrix B. Then use the following to find the variables x, y, and z.
- x = Dₓ/D
- y = Dᵧ/D
- z = D\(_z\)/D
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