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# Find the 12^{th} term of a G.P. whose 8^{th} term is 192 and the common ratio is 2

**Solution:**

Let a be the first term of the G.P

It is given that common ratio, r = 2

Eighth term of the G.P, a_{8} = 192

Therefore,

⇒ a_{8} = ar^{8 }^{- }^{1} = ar^{7}

⇒ ar^{7} = 192

⇒ a (2)^{7} = 192

⇒ a (2)^{7} = (2)^{6} (3)

⇒ a = [(2)^{6} (3)]/(2)^{7} = 3/2

Hence,

a_{12} = ar^{12 }^{- 1}

= ar^{11}

= 3/2(2)^{11}

= (3)(2)^{10}

a_{12 }= 3072

NCERT Solutions Class 11 Maths Chapter 9 Exercise 9.3 Question 2

## Find the 12^{th} term of a G.P whose 8^{th} term is 192 and the common ratio is 2

**Summary:**

We found out that the 12th term of a GP whose 8th term is 192 and whose common ratio is 2 is 3072

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